Base | Representation |
---|---|
bin | 11011010101010011011111… |
… | …110101111010000100111010 |
3 | 120202122002101012020212012001 |
4 | 123111103133311322010322 |
5 | 111224020220313144010 |
6 | 1103400150420011214 |
7 | 34214660036520655 |
oct | 3325233765720472 |
9 | 522562335225161 |
10 | 120211300131130 |
11 | 3533736502715a |
12 | 11595909230b0a |
13 | 520cb528b8b70 |
14 | 2198387c2a89c |
15 | dd6e89ba1c3a |
hex | 6d54dfd7a13a |
120211300131130 has 128 divisors (see below), whose sum is σ = 251321241036096. Its totient is φ = 41000800665600.
The previous prime is 120211300131127. The next prime is 120211300131203. The reversal of 120211300131130 is 31131003112021.
It can be written as a sum of positive squares in 32 ways, for example, as 14390391880089 + 105820908251041 = 3793467^2 + 10286929^2 .
It is a junction number, because it is equal to n+sod(n) for n = 120211300131098 and 120211300131107.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 61180264 + ... + 63114556.
Almost surely, 2120211300131130 is an apocalyptic number.
120211300131130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
120211300131130 is an abundant number, since it is smaller than the sum of its proper divisors (131109940904966).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120211300131130 is a wasteful number, since it uses less digits than its factorization.
120211300131130 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1934852.
The product of its (nonzero) digits is 108, while the sum is 19.
Adding to 120211300131130 its reverse (31131003112021), we get a palindrome (151342303243151).
The spelling of 120211300131130 in words is "one hundred twenty trillion, two hundred eleven billion, three hundred million, one hundred thirty-one thousand, one hundred thirty".
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