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121001101112 = 2315125137639
BaseRepresentation
bin111000010110000111…
…0100100011100111000
3102120022202220211001102
41300230032210130320
53440302240213422
6131330453310532
711512343250353
oct1605416443470
9376282824042
10121001101112
1147352a70211
121b54b035448
13b54471b7a8
145bdc29d29a
153232d03192
hex1c2c3a4738

121001101112 has 8 divisors (see below), whose sum is σ = 226877064600. Its totient is φ = 60500550552.

The previous prime is 121001101103. The next prime is 121001101187. The reversal of 121001101112 is 211101100121.

It is a tau number, because it is divible by the number of its divisors (8).

It is a junction number, because it is equal to n+sod(n) for n = 121001101093 and 121001101102.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 7562568812 + ... + 7562568827.

It is an arithmetic number, because the mean of its divisors is an integer number (28359633075).

Almost surely, 2121001101112 is an apocalyptic number.

It is an amenable number.

121001101112 is a deficient number, since it is larger than the sum of its proper divisors (105875963488).

121001101112 is a wasteful number, since it uses less digits than its factorization.

121001101112 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15125137645 (or 15125137641 counting only the distinct ones).

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 121001101112 its reverse (211101100121), we get a palindrome (332102201233).

Subtracting 121001101112 from its reverse (211101100121), we obtain a palindrome (90099999009).

The spelling of 121001101112 in words is "one hundred twenty-one billion, one million, one hundred one thousand, one hundred twelve".

Divisors: 1 2 4 8 15125137639 30250275278 60500550556 121001101112