12101012111 has 2 divisors, whose sum is σ = 12101012112. Its totient is φ = 12101012110.

The previous prime is 12101012089. The next prime is 12101012113. The reversal of 12101012111 is 11121010121.

12101012111 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12101012111 is a prime.

It is a super-2 number, since 2×12101012111² (a number of 21 digits) contains 22 as substring.

Together with 12101012113, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 12101012092 and 12101012101.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (12101012113) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6050506055 + 6050506056.

It is an arithmetic number, because the mean of its divisors is an integer number (6050506056).

Almost surely, 2^12101012111 is an apocalyptic number.

12101012111 is a deficient number, since it is larger than the sum of its proper divisors (1).

12101012111 is an equidigital number, since it uses as much as digits as its factorization.

12101012111 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 4, while the sum is 11.

Adding to 12101012111 its reverse (11121010121), we get a palindrome (23222022232).

It can be divided in two parts, 121010121 and 11, that multiplied together give a palindrome (1331111331).

The spelling of 12101012111 in words is "twelve billion, one hundred one million, twelve thousand, one hundred eleven".