121113434232 has 48 divisors (see below), whose sum is σ = 374874917040. Its totient is φ = 34603838208.

The previous prime is 121113434231. The next prime is 121113434353. The reversal of 121113434232 is 232434311121.

121113434232 is a `hidden beast` number, since 1 + 211 + 13 + 434 + 2 + 3 + 2 = 666.

It is a nude number because it is divisible by every one of its digits.

It is a junction number, because it is equal to n+sod(n) for n = 121113434196 and 121113434205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (121113434231) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 120151713 + ... + 120152720.

It is an arithmetic number, because the mean of its divisors is an integer number (7809894105).

Almost surely, 2^121113434232 is an apocalyptic number.

121113434232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

121113434232 is an abundant number, since it is smaller than the sum of its proper divisors (253761482808).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121113434232 is a wasteful number, since it uses less digits than its factorization.

121113434232 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 240304452 (or 240304445 counting only the distinct ones).

The product of its digits is 3456, while the sum is 27.

Adding to 121113434232 its reverse (232434311121), we get a palindrome (353547745353).

The spelling of 121113434232 in words is "one hundred twenty-one billion, one hundred thirteen million, four hundred thirty-four thousand, two hundred thirty-two".