Base | Representation |
---|---|
bin | 1011000001001100000010… |
… | …1011001001100011011000 |
3 | 1120220012000222201102201200 |
4 | 2300103000223021203120 |
5 | 3041443100304432022 |
6 | 41433323411114200 |
7 | 2360165664353505 |
oct | 260230053114330 |
9 | 46805028642650 |
10 | 12115040311512 |
11 | 3950a61465616 |
12 | 1437b865a2960 |
13 | 69b59c1c0928 |
14 | 2dc52a3584ac |
15 | 160217783bac |
hex | b04c0ac98d8 |
12115040311512 has 96 divisors (see below), whose sum is σ = 33079588542000. Its totient is φ = 4005392302080.
The previous prime is 12115040311501. The next prime is 12115040311559. The reversal of 12115040311512 is 21511304051121.
12115040311512 is a `hidden beast` number, since 1 + 2 + 1 + 1 + 504 + 0 + 3 + 1 + 151 + 2 = 666.
It is a super-2 number, since 2×121150403115122 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 17477064 + ... + 18157032.
Almost surely, 212115040311512 is an apocalyptic number.
12115040311512 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 12115040311512, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16539794271000).
12115040311512 is an abundant number, since it is smaller than the sum of its proper divisors (20964548230488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12115040311512 is a wasteful number, since it uses less digits than its factorization.
12115040311512 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 682001 (or 681994 counting only the distinct ones).
The product of its (nonzero) digits is 1200, while the sum is 27.
Adding to 12115040311512 its reverse (21511304051121), we get a palindrome (33626344362633).
The spelling of 12115040311512 in words is "twelve trillion, one hundred fifteen billion, forty million, three hundred eleven thousand, five hundred twelve".
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