Base | Representation |
---|---|
bin | 111000011111010110… |
… | …1001111010111011100 |
3 | 102121010101021222020120 |
4 | 1300332231033113130 |
5 | 3441421122143400 |
6 | 131421330314540 |
7 | 11523126413025 |
oct | 1607655172734 |
9 | 377111258216 |
10 | 121311131100 |
11 | 474a1a75345 |
12 | 1b616a28a50 |
13 | b593a1b9a3 |
14 | 5c2b523c4c |
15 | 3250143ca0 |
hex | 1c3eb4f5dc |
121311131100 has 72 divisors (see below), whose sum is σ = 351028449408. Its totient is φ = 32346417600.
The previous prime is 121311131093. The next prime is 121311131107. The reversal of 121311131100 is 1131113121.
121311131100 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (121311131093) and next prime (121311131107).
It is a super-2 number, since 2×1213111311002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 121311131100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (121311131107) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6011227 + ... + 6031373.
Almost surely, 2121311131100 is an apocalyptic number.
121311131100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
121311131100 is an abundant number, since it is smaller than the sum of its proper divisors (229717318308).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121311131100 is a wasteful number, since it uses less digits than its factorization.
121311131100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 40235 (or 40228 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 15.
Adding to 121311131100 its reverse (1131113121), we get a palindrome (122442244221).
The spelling of 121311131100 in words is "one hundred twenty-one billion, three hundred eleven million, one hundred thirty-one thousand, one hundred".
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