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123432113510055 = 325721719473687391
BaseRepresentation
bin11100000100001011000111…
…010001111001011010100111
3121012000222212012212000111200
4130010023013101321122213
5112134302432024310210
61114303532524333543
734666450560524100
oct3404130721713247
9535028765760450
10123432113510055
11363692a1231739
1211a15b790a42b3
1353b47a179b25c
14226a2091393a7
15e40b44c020c0
hex7042c74796a7

123432113510055 has 288 divisors, whose sum is σ = 283290822696960. Its totient is φ = 49241347061760.

The previous prime is 123432113510051. The next prime is 123432113510087. The reversal of 123432113510055 is 550015311234321.

It is a happy number.

123432113510055 is a `hidden beast` number, since 1 + 2 + 3 + 43 + 211 + 351 + 0 + 0 + 55 = 666.

It is not a de Polignac number, because 123432113510055 - 22 = 123432113510051 is a prime.

It is a super-2 number, since 2×1234321135100552 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (123432113510051) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 31630410 + ... + 35317800.

It is an arithmetic number, because the mean of its divisors is an integer number (983648689920).

Almost surely, 2123432113510055 is an apocalyptic number.

123432113510055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

123432113510055 is an abundant number, since it is smaller than the sum of its proper divisors (159858709186905).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

123432113510055 is a wasteful number, since it uses less digits than its factorization.

123432113510055 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3687499 (or 3687489 counting only the distinct ones).

The product of its (nonzero) digits is 54000, while the sum is 36.

Adding to 123432113510055 its reverse (550015311234321), we get a palindrome (673447424744376).

The spelling of 123432113510055 in words is "one hundred twenty-three trillion, four hundred thirty-two billion, one hundred thirteen million, five hundred ten thousand, fifty-five".