Base | Representation |
---|---|
bin | 10110111111101010… |
… | …01111100110100111 |
3 | 1011212100200201020021 |
4 | 23133311033212213 |
5 | 200240333230203 |
6 | 5401000420011 |
7 | 614632364455 |
oct | 133765174647 |
9 | 34770621207 |
10 | 12345211303 |
11 | 5265605a77 |
12 | 2486477607 |
13 | 1219832179 |
14 | 8517dd9d5 |
15 | 4c3c105bd |
hex | 2dfd4f9a7 |
12345211303 has 2 divisors, whose sum is σ = 12345211304. Its totient is φ = 12345211302.
The previous prime is 12345211279. The next prime is 12345211327. The reversal of 12345211303 is 30311254321.
It is a happy number.
It is a balanced prime because it is at equal distance from previous prime (12345211279) and next prime (12345211327).
It is an emirp because it is prime and its reverse (30311254321) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 12345211303 - 229 = 11808340391 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (12345215303) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6172605651 + 6172605652.
It is an arithmetic number, because the mean of its divisors is an integer number (6172605652).
Almost surely, 212345211303 is an apocalyptic number.
12345211303 is a deficient number, since it is larger than the sum of its proper divisors (1).
12345211303 is an equidigital number, since it uses as much as digits as its factorization.
12345211303 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 12345211303 its reverse (30311254321), we get a palindrome (42656465624).
The spelling of 12345211303 in words is "twelve billion, three hundred forty-five million, two hundred eleven thousand, three hundred three".
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