Base | Representation |
---|---|
bin | 10111000000010000… |
… | …10010000010011111 |
3 | 1011212201002021012110 |
4 | 23200020102002133 |
5 | 200243122431030 |
6 | 5401255405103 |
7 | 615022661604 |
oct | 134010220237 |
9 | 34781067173 |
10 | 12350202015 |
11 | 5268404628 |
12 | 2488083793 |
13 | 121a88b958 |
14 | 85233c6ab |
15 | 4c43991b0 |
hex | 2e021209f |
12350202015 has 64 divisors (see below), whose sum is σ = 21393331200. Its totient is φ = 6065224704.
The previous prime is 12350202001. The next prime is 12350202031. The reversal of 12350202015 is 51020205321.
It is not a de Polignac number, because 12350202015 - 27 = 12350201887 is a prime.
It is a super-2 number, since 2×123502020152 (a number of 21 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 12350201982 and 12350202000.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 3790267 + ... + 3793523.
It is an arithmetic number, because the mean of its divisors is an integer number (334270800).
Almost surely, 212350202015 is an apocalyptic number.
12350202015 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12350202015 is a deficient number, since it is larger than the sum of its proper divisors (9043129185).
12350202015 is a wasteful number, since it uses less digits than its factorization.
12350202015 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3696.
The product of its (nonzero) digits is 600, while the sum is 21.
Adding to 12350202015 its reverse (51020205321), we get a palindrome (63370407336).
The spelling of 12350202015 in words is "twelve billion, three hundred fifty million, two hundred two thousand, fifteen".
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