Base | Representation |
---|---|
bin | 1110110010001… |
… | …00101000101100 |
3 | 22122100111222210 |
4 | 13121010220230 |
5 | 223221404400 |
6 | 20150010420 |
7 | 3034044141 |
oct | 731045054 |
9 | 278314883 |
10 | 124013100 |
11 | 64002972 |
12 | 35646a10 |
13 | 1c900743 |
14 | 126823c8 |
15 | ad49950 |
hex | 7644a2c |
124013100 has 72 divisors (see below), whose sum is σ = 359976960. Its totient is φ = 32962880.
The previous prime is 124013083. The next prime is 124013117. The reversal of 124013100 is 1310421.
It is a happy number.
It is an interprime number because it is at equal distance from previous prime (124013083) and next prime (124013117).
It is a super-2 number, since 2×1240131002 = 30758497943220000, which contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (12).
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 143269 + ... + 144131.
It is an arithmetic number, because the mean of its divisors is an integer number (4999680).
Almost surely, 2124013100 is an apocalyptic number.
124013100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 124013100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (179988480).
124013100 is an abundant number, since it is smaller than the sum of its proper divisors (235963860).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
124013100 is a wasteful number, since it uses less digits than its factorization.
124013100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1359 (or 1352 counting only the distinct ones).
The product of its (nonzero) digits is 24, while the sum is 12.
The square root of 124013100 is about 11136.1169174897. The cubic root of 124013100 is about 498.6806550532.
Adding to 124013100 its reverse (1310421), we get a palindrome (125323521).
The spelling of 124013100 in words is "one hundred twenty-four million, thirteen thousand, one hundred".
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