Base | Representation |
---|---|
bin | 11101100011111111010101… |
… | …110000110010110001110000 |
3 | 122001100110102022111012012001 |
4 | 131203333111300302301300 |
5 | 114020142334041330440 |
6 | 1140304435144343344 |
7 | 36246246045666550 |
oct | 3543772560626160 |
9 | 561313368435161 |
10 | 130016541355120 |
11 | 38477784086152 |
12 | 126ba0b0774b54 |
13 | 5771679542a94 |
14 | 2416b96dad160 |
15 | 1007066875b9a |
hex | 763fd5c32c70 |
130016541355120 has 120 divisors (see below), whose sum is σ = 350705797079904. Its totient is φ = 43911769195008.
The previous prime is 130016541355117. The next prime is 130016541355147. The reversal of 130016541355120 is 21553145610031.
It is a self number, because there is not a number n which added to its sum of digits gives 130016541355120.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 23346307 + ... + 28373986.
Almost surely, 2130016541355120 is an apocalyptic number.
130016541355120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130016541355120 is an abundant number, since it is smaller than the sum of its proper divisors (220689255724784).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130016541355120 is an equidigital number, since it uses as much as digits as its factorization.
130016541355120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 51720447 (or 51720374 counting only the distinct ones).
The product of its (nonzero) digits is 54000, while the sum is 37.
Adding to 130016541355120 its reverse (21553145610031), we get a palindrome (151569686965151).
The spelling of 130016541355120 in words is "one hundred thirty trillion, sixteen billion, five hundred forty-one million, three hundred fifty-five thousand, one hundred twenty".
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