Base | Representation |
---|---|
bin | 10010111010111010100… |
… | …100010101101001110000 |
3 | 11121022001212220022010001 |
4 | 102322322210111221300 |
5 | 132300312303231230 |
6 | 2433150333115344 |
7 | 162636264305620 |
oct | 22727244255160 |
9 | 4538055808101 |
10 | 1300210211440 |
11 | 46146384a158 |
12 | 18bba5928b54 |
13 | 957bc8185ca |
14 | 46d05468880 |
15 | 23c4c5ea0ca |
hex | 12eba915a70 |
1300210211440 has 40 divisors (see below), whose sum is σ = 3454844277600. Its totient is φ = 445786358016.
The previous prime is 1300210211401. The next prime is 1300210211471. The reversal of 1300210211440 is 441120120031.
It is a tau number, because it is divible by the number of its divisors (40).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1160901415 + ... + 1160902534.
It is an arithmetic number, because the mean of its divisors is an integer number (86371106940).
Almost surely, 21300210211440 is an apocalyptic number.
1300210211440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1300210211440 is an abundant number, since it is smaller than the sum of its proper divisors (2154634066160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300210211440 is a wasteful number, since it uses less digits than its factorization.
1300210211440 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2321803969 (or 2321803963 counting only the distinct ones).
The product of its (nonzero) digits is 192, while the sum is 19.
Adding to 1300210211440 its reverse (441120120031), we get a palindrome (1741330331471).
The spelling of 1300210211440 in words is "one trillion, three hundred billion, two hundred ten million, two hundred eleven thousand, four hundred forty".
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