Base | Representation |
---|---|
bin | 11000001101111110… |
… | …11111111100011100 |
3 | 1020120010221202112002 |
4 | 30012333133330130 |
5 | 203112031223400 |
6 | 5550110301432 |
7 | 640130653664 |
oct | 140677377434 |
9 | 36503852462 |
10 | 13002211100 |
11 | 557245570a |
12 | 262a4b7878 |
13 | 12c2997248 |
14 | 8b4b831a4 |
15 | 51173bed5 |
hex | 306fdff1c |
13002211100 has 72 divisors (see below), whose sum is σ = 30424354800. Its totient is φ = 4806950400.
The previous prime is 13002211097. The next prime is 13002211111. The reversal of 13002211100 is 111220031.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5555 + ... + 161354.
Almost surely, 213002211100 is an apocalyptic number.
13002211100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13002211100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15212177400).
13002211100 is an abundant number, since it is smaller than the sum of its proper divisors (17422143700).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13002211100 is a wasteful number, since it uses less digits than its factorization.
13002211100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 166983 (or 166976 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 13002211100 its reverse (111220031), we get a palindrome (13113431131).
The spelling of 13002211100 in words is "thirteen billion, two million, two hundred eleven thousand, one hundred".
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