Base | Representation |
---|---|
bin | 1111100000000… |
… | …00011010011000 |
3 | 100001122221220220 |
4 | 13300000122120 |
5 | 231241300422 |
6 | 20522520040 |
7 | 3136123650 |
oct | 760003230 |
9 | 301587826 |
10 | 130025112 |
11 | 67439878 |
12 | 37666020 |
13 | 20c27049 |
14 | 133a9360 |
15 | b635e5c |
hex | 7c00698 |
130025112 has 128 divisors (see below), whose sum is σ = 401241600. Its totient is φ = 34265088.
The previous prime is 130025111. The next prime is 130025117. The reversal of 130025112 is 211520031.
It is a super-2 number, since 2×1300251122 = 33813059501225088, which contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 130025091 and 130025100.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130025111) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 150939 + ... + 151797.
It is an arithmetic number, because the mean of its divisors is an integer number (3134700).
Almost surely, 2130025112 is an apocalyptic number.
130025112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 130025112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (200620800).
130025112 is an abundant number, since it is smaller than the sum of its proper divisors (271216488).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130025112 is a wasteful number, since it uses less digits than its factorization.
130025112 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 945 (or 941 counting only the distinct ones).
The product of its (nonzero) digits is 60, while the sum is 15.
The square root of 130025112 is about 11402.8554318644. The cubic root of 130025112 is about 506.6123183471.
Adding to 130025112 its reverse (211520031), we get a palindrome (341545143).
The spelling of 130025112 in words is "one hundred thirty million, twenty-five thousand, one hundred twelve".
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