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130025112 = 23371753859
BaseRepresentation
bin1111100000000…
…00011010011000
3100001122221220220
413300000122120
5231241300422
620522520040
73136123650
oct760003230
9301587826
10130025112
1167439878
1237666020
1320c27049
14133a9360
15b635e5c
hex7c00698

130025112 has 128 divisors (see below), whose sum is σ = 401241600. Its totient is φ = 34265088.

The previous prime is 130025111. The next prime is 130025117. The reversal of 130025112 is 211520031.

It is a super-2 number, since 2×1300251122 = 33813059501225088, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 130025091 and 130025100.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130025111) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 150939 + ... + 151797.

It is an arithmetic number, because the mean of its divisors is an integer number (3134700).

Almost surely, 2130025112 is an apocalyptic number.

130025112 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 130025112, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (200620800).

130025112 is an abundant number, since it is smaller than the sum of its proper divisors (271216488).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130025112 is a wasteful number, since it uses less digits than its factorization.

130025112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 945 (or 941 counting only the distinct ones).

The product of its (nonzero) digits is 60, while the sum is 15.

The square root of 130025112 is about 11402.8554318644. The cubic root of 130025112 is about 506.6123183471.

Adding to 130025112 its reverse (211520031), we get a palindrome (341545143).

The spelling of 130025112 in words is "one hundred thirty million, twenty-five thousand, one hundred twelve".

Divisors: 1 2 3 4 6 7 8 12 14 17 21 24 28 34 42 51 53 56 68 84 102 106 119 136 159 168 204 212 238 318 357 371 408 424 476 636 714 742 859 901 952 1113 1272 1428 1484 1718 1802 2226 2577 2703 2856 2968 3436 3604 4452 5154 5406 6013 6307 6872 7208 8904 10308 10812 12026 12614 14603 18039 18921 20616 21624 24052 25228 29206 36078 37842 43809 45527 48104 50456 58412 72156 75684 87618 91054 102221 116824 136581 144312 151368 175236 182108 204442 273162 306663 318689 350472 364216 408884 546324 613326 637378 773959 817768 956067 1092648 1226652 1274756 1547918 1912134 2321877 2453304 2549512 3095836 3824268 4643754 5417713 6191672 7648536 9287508 10835426 16253139 18575016 21670852 32506278 43341704 65012556 130025112