13003100113300 has 54 divisors (see below), whose sum is σ = 31015080390014. Its totient is φ = 4728400036800.

The previous prime is 13003100113277. The next prime is 13003100113309. The reversal of 13003100113300 is 331100130031.

It can be written as a sum of positive squares in 3 ways, for example, as 174926370564 + 12828173742736 = 418242^2 + 3581644^2 .

It is a super-2 number, since 2×13003100113300² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13003100113309) by changing a digit.

It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 537306087 + ... + 537330286.

Almost surely, 2^{13003100113300} is an apocalyptic number.

13003100113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13003100113300 is an abundant number, since it is smaller than the sum of its proper divisors (18011980276714).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13003100113300 is a wasteful number, since it uses less digits than its factorization.

13003100113300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1074636409 (or 1074636391 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 13003100113300 its reverse (331100130031), we get a palindrome (13334200243331).

The spelling of 13003100113300 in words is "thirteen trillion, three billion, one hundred million, one hundred thirteen thousand, three hundred".