Base | Representation |
---|---|
bin | 10010111011000000100… |
… | …101010010010101110000 |
3 | 11121022022220210011011210 |
4 | 102323000211102111300 |
5 | 132301014121421222 |
6 | 2433204340040120 |
7 | 162641631116415 |
oct | 22730045222560 |
9 | 4538286704153 |
10 | 1300311123312 |
11 | 4615058037a3 |
12 | 190013693040 |
13 | 958076bb186 |
14 | 46d14a1610c |
15 | 23c563ced0c |
hex | 12ec0952570 |
1300311123312 has 80 divisors (see below), whose sum is σ = 3416379294080. Its totient is φ = 426060000000.
The previous prime is 1300311123299. The next prime is 1300311123341. The reversal of 1300311123312 is 2133211130031.
It is a happy number.
It is a super-3 number, since 3×13003111233123 (a number of 37 digits) contains 333 as substring.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 4482687 + ... + 4763937.
It is an arithmetic number, because the mean of its divisors is an integer number (42704741176).
Almost surely, 21300311123312 is an apocalyptic number.
1300311123312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1300311123312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1708189647040).
1300311123312 is an abundant number, since it is smaller than the sum of its proper divisors (2116068170768).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1300311123312 is a wasteful number, since it uses less digits than its factorization.
1300311123312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 282902 (or 282896 counting only the distinct ones).
The product of its (nonzero) digits is 324, while the sum is 21.
Adding to 1300311123312 its reverse (2133211130031), we get a palindrome (3433522253343).
The spelling of 1300311123312 in words is "one trillion, three hundred billion, three hundred eleven million, one hundred twenty-three thousand, three hundred twelve".
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