130044014320 has 60 divisors (see below), whose sum is σ = 332337713400. Its totient is φ = 47288728960.

The previous prime is 130044014311. The next prime is 130044014323. The reversal of 130044014320 is 23410440031.

It is a super-2 number, since 2×130044014320² (a number of 23 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 130044014291 and 130044014300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130044014323) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6707470 + ... + 6726829.

It is an arithmetic number, because the mean of its divisors is an integer number (5538961890).

Almost surely, 2^130044014320 is an apocalyptic number.

130044014320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130044014320 is an abundant number, since it is smaller than the sum of its proper divisors (202293699080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130044014320 is a wasteful number, since it uses less digits than its factorization.

130044014320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13434334 (or 13434317 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 22.

Adding to 130044014320 its reverse (23410440031), we get a palindrome (153454454351).

The spelling of 130044014320 in words is "one hundred thirty billion, forty-four million, fourteen thousand, three hundred twenty".