Base | Representation |
---|---|
bin | 11000001110011000… |
… | …10000000110110100 |
3 | 1020120101020121020220 |
4 | 30013030100012310 |
5 | 203113410212400 |
6 | 5550310054340 |
7 | 640201246230 |
oct | 140714200664 |
9 | 36511217226 |
10 | 13005554100 |
11 | 5574329320 |
12 | 262b64a3b0 |
13 | 12c3597a56 |
14 | 8b53b35c0 |
15 | 511b9c7a0 |
hex | 3073101b4 |
13005554100 has 144 divisors (see below), whose sum is σ = 46914663936. Its totient is φ = 2702448000.
The previous prime is 13005554071. The next prime is 13005554119. The reversal of 13005554100 is 145550031.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 258406 + ... + 304605.
Almost surely, 213005554100 is an apocalyptic number.
13005554100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13005554100 is an abundant number, since it is smaller than the sum of its proper divisors (33909109836).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13005554100 is a wasteful number, since it uses less digits than its factorization.
13005554100 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 563046 (or 563039 counting only the distinct ones).
The product of its (nonzero) digits is 1500, while the sum is 24.
The spelling of 13005554100 in words is "thirteen billion, five million, five hundred fifty-four thousand, one hundred".
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