Base | Representation |
---|---|
bin | 11101100100101100111001… |
… | …110010011010100110101010 |
3 | 122001112010200211100021112221 |
4 | 131210230321302122212222 |
5 | 114021443032310023000 |
6 | 1140343125505424254 |
7 | 36252630310554160 |
oct | 3544547162324652 |
9 | 561463624307487 |
10 | 130065464142250 |
11 | 384964a978822a |
12 | 1270768493b08a |
13 | 577617507ca30 |
14 | 24192b8613230 |
15 | 100847b88661a |
hex | 764b39c9a9aa |
130065464142250 has 128 divisors (see below), whose sum is σ = 300271398336000. Its totient is φ = 41081079744000.
The previous prime is 130065464142227. The next prime is 130065464142287. The reversal of 130065464142250 is 52241464560031.
It is a junction number, because it is equal to n+sod(n) for n = 130065464142197 and 130065464142206.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 5623630 + ... + 17080870.
It is an arithmetic number, because the mean of its divisors is an integer number (2345870299500).
Almost surely, 2130065464142250 is an apocalyptic number.
130065464142250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130065464142250 is an abundant number, since it is smaller than the sum of its proper divisors (170205934193750).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130065464142250 is a wasteful number, since it uses less digits than its factorization.
130065464142250 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11457777 (or 11457767 counting only the distinct ones).
The product of its (nonzero) digits is 691200, while the sum is 43.
The spelling of 130065464142250 in words is "one hundred thirty trillion, sixty-five billion, four hundred sixty-four million, one hundred forty-two thousand, two hundred fifty".
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