1301110101013 has 4 divisors (see below), whose sum is σ = 1307276499808. Its totient is φ = 1294943702220.

The previous prime is 1301110100951. The next prime is 1301110101023. The reversal of 1301110101013 is 3101010111031.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1301110101013 - 2¹⁷ = 1301109969941 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1301110100984 and 1301110101002.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1301110101023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3083199081 + ... + 3083199502.

It is an arithmetic number, because the mean of its divisors is an integer number (326819124952).

Almost surely, 2^{1301110101013} is an apocalyptic number.

It is an amenable number.

1301110101013 is a deficient number, since it is larger than the sum of its proper divisors (6166398795).

1301110101013 is an equidigital number, since it uses as much as digits as its factorization.

1301110101013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6166398794.

The product of its (nonzero) digits is 9, while the sum is 13.

Adding to 1301110101013 its reverse (3101010111031), we get a palindrome (4402120212044).

The spelling of 1301110101013 in words is "one trillion, three hundred one billion, one hundred ten million, one hundred one thousand, thirteen".