130211111400320 has 32 divisors (see below), whose sum is σ = 311285938192920. Its totient is φ = 52084444559872.

The previous prime is 130211111400233. The next prime is 130211111400347. The reversal of 130211111400320 is 23004111112031.

It is a tau number, because it is divible by the number of its divisors (32).

It is a super-2 number, since 2×130211111400320² (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a junction number, because it is equal to n+sod(n) for n = 130211111400292 and 130211111400301.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 101727430142 + ... + 101727431421.

Almost surely, 2^{130211111400320} is an apocalyptic number.

130211111400320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

130211111400320 is an abundant number, since it is smaller than the sum of its proper divisors (181074826792600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130211111400320 is an equidigital number, since it uses as much as digits as its factorization.

130211111400320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 203454861582 (or 203454861570 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 130211111400320 its reverse (23004111112031), we get a palindrome (153215222512351).

The spelling of 130211111400320 in words is "one hundred thirty trillion, two hundred eleven billion, one hundred eleven million, four hundred thousand, three hundred twenty".