Base | Representation |
---|---|
bin | 11101101000100110010110… |
… | …101101001101011110100000 |
3 | 122002110202001112112000211020 |
4 | 131220212112231031132200 |
5 | 114040340110110444300 |
6 | 1141110144014045440 |
7 | 36311161642551144 |
oct | 3550462655153640 |
9 | 562422045460736 |
10 | 130333311031200 |
11 | 3858a057327282 |
12 | 1274b5761a9880 |
13 | 57954bc721234 |
14 | 2428247397224 |
15 | 10104063b28a0 |
hex | 768996b4d7a0 |
130333311031200 has 72 divisors (see below), whose sum is σ = 424234927414368. Its totient is φ = 34755549607680.
The previous prime is 130333311031199. The next prime is 130333311031303. The reversal of 130333311031200 is 2130113333031.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is an unprimeable number.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 27152770732 + ... + 27152775531.
It is an arithmetic number, because the mean of its divisors is an integer number (5892151769644).
Almost surely, 2130333311031200 is an apocalyptic number.
130333311031200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130333311031200 is an abundant number, since it is smaller than the sum of its proper divisors (293901616383168).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130333311031200 is a wasteful number, since it uses less digits than its factorization.
130333311031200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54305546286 (or 54305546273 counting only the distinct ones).
The product of its (nonzero) digits is 1458, while the sum is 24.
Adding to 130333311031200 its reverse (2130113333031), we get a palindrome (132463424364231).
The spelling of 130333311031200 in words is "one hundred thirty trillion, three hundred thirty-three billion, three hundred eleven million, thirty-one thousand, two hundred".
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