Base | Representation |
---|---|
bin | 11000010001111001… |
… | …00111100110010111 |
3 | 1020122102200010210000 |
4 | 30020330213212113 |
5 | 203143430313310 |
6 | 5553241302343 |
7 | 641006521635 |
oct | 141074474627 |
9 | 36572603700 |
10 | 13035010455 |
11 | 5589a18315 |
12 | 26394949b3 |
13 | 12c970c44c |
14 | 8b9280355 |
15 | 51456a4c0 |
hex | 308f27997 |
13035010455 has 40 divisors (see below), whose sum is σ = 24382413792. Its totient is φ = 6649739712.
The previous prime is 13035010441. The next prime is 13035010459. The reversal of 13035010455 is 55401053031.
It is not a de Polignac number, because 13035010455 - 27 = 13035010327 is a prime.
It is a super-2 number, since 2×130350104552 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13035010459) by changing a digit.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 690364 + ... + 708993.
Almost surely, 213035010455 is an apocalyptic number.
13035010455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
13035010455 is a deficient number, since it is larger than the sum of its proper divisors (11347403337).
13035010455 is a wasteful number, since it uses less digits than its factorization.
13035010455 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1399397 (or 1399388 counting only the distinct ones).
The product of its (nonzero) digits is 4500, while the sum is 27.
Adding to 13035010455 its reverse (55401053031), we get a palindrome (68436063486).
The spelling of 13035010455 in words is "thirteen billion, thirty-five million, ten thousand, four hundred fifty-five".
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