Base | Representation |
---|---|
bin | 11101101001110001101111… |
… | …001011101001011011100000 |
3 | 122002202110222110210111212121 |
4 | 131221301233023221123200 |
5 | 114043201342042100000 |
6 | 1141211251434234024 |
7 | 36320055514152514 |
oct | 3551615713513340 |
9 | 562673873714777 |
10 | 130414252300000 |
11 | 38610412592559 |
12 | 127631a5285914 |
13 | 57a001b86b926 |
14 | 242c125152144 |
15 | 1012592310b1a |
hex | 769c6f2e96e0 |
130414252300000 has 72 divisors (see below), whose sum is σ = 320920784020872. Its totient is φ = 52165700880000.
The previous prime is 130414252299997. The next prime is 130414252300001. The reversal of 130414252300000 is 3252414031.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130414252300001) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 651971262 + ... + 652171261.
It is an arithmetic number, because the mean of its divisors is an integer number (4457233111401).
Almost surely, 2130414252300000 is an apocalyptic number.
130414252300000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130414252300000 is an abundant number, since it is smaller than the sum of its proper divisors (190506531720872).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130414252300000 is an frugal number, since it uses more digits than its factorization.
130414252300000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1304142558 (or 1304142530 counting only the distinct ones).
The product of its (nonzero) digits is 2880, while the sum is 25.
The spelling of 130414252300000 in words is "one hundred thirty trillion, four hundred fourteen billion, two hundred fifty-two million, three hundred thousand".
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