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130554314150 = 25213200852791
BaseRepresentation
bin111100110010110100…
…1001011110110100110
3110110222112222022200112
41321211221023312212
54114333401023100
6135550440013022
712301154234411
oct1714551136646
9413875868615
10130554314150
11504055635a7
1221376461172
13c407995880
146466d5cb78
1535e1859b35
hex1e65a4bda6

130554314150 has 24 divisors (see below), whose sum is σ = 261510335184. Its totient is φ = 48204669600.

The previous prime is 130554314123. The next prime is 130554314153. The reversal of 130554314150 is 51413455031.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (130554314153) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 100425746 + ... + 100427045.

It is an arithmetic number, because the mean of its divisors is an integer number (10896263966).

Almost surely, 2130554314150 is an apocalyptic number.

130554314150 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

130554314150 is an abundant number, since it is smaller than the sum of its proper divisors (130956021034).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

130554314150 is a wasteful number, since it uses less digits than its factorization.

130554314150 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 200852816 (or 200852811 counting only the distinct ones).

The product of its (nonzero) digits is 18000, while the sum is 32.

Adding to 130554314150 its reverse (51413455031), we get a palindrome (181967769181).

The spelling of 130554314150 in words is "one hundred thirty billion, five hundred fifty-four million, three hundred fourteen thousand, one hundred fifty".

Divisors: 1 2 5 10 13 25 26 50 65 130 325 650 200852791 401705582 1004263955 2008527910 2611086283 5021319775 5222172566 10042639550 13055431415 26110862830 65277157075 130554314150