Base | Representation |
---|---|
bin | 11101101101010001100010… |
… | …111111110111100111001110 |
3 | 122010121110021100112002220222 |
4 | 131231101202333313213032 |
5 | 114111121022402214400 |
6 | 1141513513512111342 |
7 | 36343323642314162 |
oct | 3555214277674716 |
9 | 563543240462828 |
10 | 130654566054350 |
11 | 386a3321420008 |
12 | 127a1891995552 |
13 | 57b9898c45800 |
14 | 2439a01354ca2 |
15 | 1018959a96185 |
hex | 76d462ff79ce |
130654566054350 has 144 divisors (see below), whose sum is σ = 265068810831744. Its totient is φ = 47890187280000.
The previous prime is 130654566054349. The next prime is 130654566054373. The reversal of 130654566054350 is 53450665456031.
It is a junction number, because it is equal to n+sod(n) for n = 130654566054292 and 130654566054301.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 1953446009 + ... + 1953512891.
It is an arithmetic number, because the mean of its divisors is an integer number (1840755630776).
Almost surely, 2130654566054350 is an apocalyptic number.
130654566054350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
130654566054350 is an abundant number, since it is smaller than the sum of its proper divisors (134414244777394).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130654566054350 is a wasteful number, since it uses less digits than its factorization.
130654566054350 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68603 (or 68585 counting only the distinct ones).
The product of its (nonzero) digits is 19440000, while the sum is 53.
The spelling of 130654566054350 in words is "one hundred thirty trillion, six hundred fifty-four billion, five hundred sixty-six million, fifty-four thousand, three hundred fifty".
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