1310002441040 has 40 divisors (see below), whose sum is σ = 3224917777320. Its totient is φ = 493177389056.

The previous prime is 1310002441019. The next prime is 1310002441051. The reversal of 1310002441040 is 401442000131.

It can be written as a sum of positive squares in 4 ways, for example, as 192956375824 + 1117046065216 = 439268^2 + 1056904^2 .

It is a tau number, because it is divible by the number of its divisors (40).

It is a super-2 number, since 2×1310002441040² (a number of 25 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 481617185 + ... + 481619904.

It is an arithmetic number, because the mean of its divisors is an integer number (80622944433).

Almost surely, 2^{1310002441040} is an apocalyptic number.

1310002441040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1310002441040 is an abundant number, since it is smaller than the sum of its proper divisors (1914915336280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310002441040 is a wasteful number, since it uses less digits than its factorization.

1310002441040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 963237119 (or 963237113 counting only the distinct ones).

The product of its (nonzero) digits is 384, while the sum is 20.

Adding to 1310002441040 its reverse (401442000131), we get a palindrome (1711444441171).

The spelling of 1310002441040 in words is "one trillion, three hundred ten billion, two million, four hundred forty-one thousand, forty".