13100040443440 has 160 divisors (see below), whose sum is σ = 33185952927360. Its totient is φ = 4789051932672.

The previous prime is 13100040443419. The next prime is 13100040443443. The reversal of 13100040443440 is 4434404000131.

It is a happy number.

It is a super-2 number, since 2×13100040443440² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 13100040443399 and 13100040443408.

It is not an unprimeable number, because it can be changed into a prime (13100040443443) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 25357149 + ... + 25868611.

It is an arithmetic number, because the mean of its divisors is an integer number (207412205796).

Almost surely, 2^{13100040443440} is an apocalyptic number.

13100040443440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13100040443440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16592976463680).

13100040443440 is an abundant number, since it is smaller than the sum of its proper divisors (20085912483920).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100040443440 is a wasteful number, since it uses less digits than its factorization.

13100040443440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 512039 (or 512033 counting only the distinct ones).

The product of its (nonzero) digits is 9216, while the sum is 28.

Adding to 13100040443440 its reverse (4434404000131), we get a palindrome (17534444443571).

The spelling of 13100040443440 in words is "thirteen trillion, one hundred billion, forty million, four hundred forty-three thousand, four hundred forty".