Base | Representation |
---|---|
bin | 111101000000011011… |
… | …1101111000101010100 |
3 | 110112011101112010022120 |
4 | 1322000313233011110 |
5 | 4121302321111200 |
6 | 140104034455540 |
7 | 12315402042354 |
oct | 1720067570524 |
9 | 415141463276 |
10 | 131011113300 |
11 | 5061a3a3561 |
12 | 214834345b0 |
13 | c47b503222 |
14 | 64ab8aab64 |
15 | 361b9dc9a0 |
hex | 1e80def154 |
131011113300 has 72 divisors (see below), whose sum is σ = 389303687136. Its totient is φ = 33992069760.
The previous prime is 131011113293. The next prime is 131011113323. The reversal of 131011113300 is 3311110131.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 131011113300.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 5890302 + ... + 5912501.
Almost surely, 2131011113300 is an apocalyptic number.
131011113300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131011113300 is an abundant number, since it is smaller than the sum of its proper divisors (258292573836).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131011113300 is a wasteful number, since it uses less digits than its factorization.
131011113300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 11802857 (or 11802850 counting only the distinct ones).
The product of its (nonzero) digits is 27, while the sum is 15.
Adding to 131011113300 its reverse (3311110131), we get a palindrome (134322223431).
The spelling of 131011113300 in words is "one hundred thirty-one billion, eleven million, one hundred thirteen thousand, three hundred".
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