1310112100000 has 144 divisors (see below), whose sum is σ = 3516982211232. Its totient is φ = 476404000000.

The previous prime is 1310112099979. The next prime is 1310112100007. The reversal of 1310112100000 is 12110131.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a self number, because there is not a number n which added to its sum of digits gives 1310112100000.

It is not an unprimeable number, because it can be changed into a prime (1310112100007) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 504495 + ... + 1695505.

It is an arithmetic number, because the mean of its divisors is an integer number (24423487578).

Almost surely, 2^{1310112100000} is an apocalyptic number.

1310112100000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1310112100000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1758491105616).

1310112100000 is an abundant number, since it is smaller than the sum of its proper divisors (2206870111232).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1310112100000 is an equidigital number, since it uses as much as digits as its factorization.

1310112100000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1191057 (or 1191029 counting only the distinct ones).

The product of its (nonzero) digits is 6, while the sum is 10.

Adding to 1310112100000 its reverse (12110131), we get a palindrome (1310124210131).

The spelling of 1310112100000 in words is "one trillion, three hundred ten billion, one hundred twelve million, one hundred thousand".