Base | Representation |
---|---|
bin | 1011111010100110001110… |
… | …0110001101000011101100 |
3 | 1201101110210121020101212011 |
4 | 2332221203212031003230 |
5 | 3204123001212242030 |
6 | 43510355221451004 |
7 | 2521352644605340 |
oct | 276514346150354 |
9 | 51343717211764 |
10 | 13101321212140 |
11 | 41a126a301057 |
12 | 1577159b70a64 |
13 | 7405ac11bb95 |
14 | 334170729620 |
15 | 17abde8a1b2a |
hex | bea6398d0ec |
13101321212140 has 96 divisors (see below), whose sum is σ = 31590875433600. Its totient is φ = 4470793850880.
The previous prime is 13101321212107. The next prime is 13101321212149. The reversal of 13101321212140 is 4121212310131.
It is not an unprimeable number, because it can be changed into a prime (13101321212149) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 99608820 + ... + 99740260.
It is an arithmetic number, because the mean of its divisors is an integer number (329071619100).
Almost surely, 213101321212140 is an apocalyptic number.
13101321212140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13101321212140, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15795437716800).
13101321212140 is an abundant number, since it is smaller than the sum of its proper divisors (18489554221460).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13101321212140 is a wasteful number, since it uses less digits than its factorization.
13101321212140 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 134795 (or 134793 counting only the distinct ones).
The product of its (nonzero) digits is 288, while the sum is 22.
Adding to 13101321212140 its reverse (4121212310131), we get a palindrome (17222533522271).
The spelling of 13101321212140 in words is "thirteen trillion, one hundred one billion, three hundred twenty-one million, two hundred twelve thousand, one hundred forty".
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