Base | Representation |
---|---|
bin | 1011111010101001001010… |
… | …1011000111101011110000 |
3 | 1201101112211122102022021111 |
4 | 2332222102223013223300 |
5 | 3204131110410430000 |
6 | 43511005434203104 |
7 | 2521411345133326 |
oct | 276522253075360 |
9 | 51345748368244 |
10 | 13102111030000 |
11 | 41a1635117993 |
12 | 157733a583494 |
13 | 7406a6948325 |
14 | 3342075a3d16 |
15 | 17ac38db6cba |
hex | bea92ac7af0 |
13102111030000 has 50 divisors (see below), whose sum is σ = 31721521038944. Its totient is φ = 5240844408000.
The previous prime is 13102111029967. The next prime is 13102111030051. The reversal of 13102111030000 is 3011120131.
It is a tau number, because it is divible by the number of its divisors (50).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 655095552 + ... + 655115551.
Almost surely, 213102111030000 is an apocalyptic number.
13102111030000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13102111030000 is an abundant number, since it is smaller than the sum of its proper divisors (18619410008944).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102111030000 is an equidigital number, since it uses as much as digits as its factorization.
13102111030000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1310211131 (or 1310211110 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 13102111030000 its reverse (3011120131), we get a palindrome (13105122150131).
The spelling of 13102111030000 in words is "thirteen trillion, one hundred two billion, one hundred eleven million, thirty thousand".
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