131022011410000 has 100 divisors (see below), whose sum is σ = 317431619057124. Its totient is φ = 52373411200000.

The previous prime is 131022011409983. The next prime is 131022011410063. The reversal of 131022011410000 is 14110220131.

It can be written as a sum of positive squares in 10 ways, for example, as 90158671116864 + 40863340293136 = 9495192^2 + 6392444^2 .

It is a tau number, because it is divible by the number of its divisors (100).

It is a Harshad number since it is a multiple of its sum of digits (16).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 10386570 + ... + 19233430.

Almost surely, 2^{131022011410000} is an apocalyptic number.

131022011410000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131022011410000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158715809528562).

131022011410000 is an abundant number, since it is smaller than the sum of its proper divisors (186409607647124).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131022011410000 is an equidigital number, since it uses as much as digits as its factorization.

131022011410000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8848370 (or 8848349 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 131022011410000 its reverse (14110220131), we get a palindrome (131036121630131).

The spelling of 131022011410000 in words is "one hundred thirty-one trillion, twenty-two billion, eleven million, four hundred ten thousand".