Base | Representation |
---|---|
bin | 1011111010101001100010… |
… | …1101110111001101010000 |
3 | 1201101120002201012001120021 |
4 | 2332222120231313031100 |
5 | 3204131312334142430 |
6 | 43511023455153224 |
7 | 2521414015643350 |
oct | 276523055671520 |
9 | 51346081161507 |
10 | 13102212412240 |
11 | 41a1687372966 |
12 | 1577368515814 |
13 | 7406c1954013 |
14 | 334216c34b60 |
15 | 17ac42c4107a |
hex | bea98b77350 |
13102212412240 has 80 divisors (see below), whose sum is σ = 36646789633920. Its totient is φ = 4255756208640.
The previous prime is 13102212412231. The next prime is 13102212412301. The reversal of 13102212412240 is 4221421220131.
It is a tau number, because it is divible by the number of its divisors (80).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 615694831 + ... + 615716110.
It is an arithmetic number, because the mean of its divisors is an integer number (458084870424).
Almost surely, 213102212412240 is an apocalyptic number.
13102212412240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13102212412240 is an abundant number, since it is smaller than the sum of its proper divisors (23544577221680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102212412240 is a wasteful number, since it uses less digits than its factorization.
13102212412240 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1231410980 (or 1231410974 counting only the distinct ones).
The product of its (nonzero) digits is 1536, while the sum is 25.
Adding to 13102212412240 its reverse (4221421220131), we get a palindrome (17323633632371).
The spelling of 13102212412240 in words is "thirteen trillion, one hundred two billion, two hundred twelve million, four hundred twelve thousand, two hundred forty".
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