13103011320 has 64 divisors (see below), whose sum is σ = 44924613120. Its totient is φ = 2994973824.

The previous prime is 13103011319. The next prime is 13103011321. The reversal of 13103011320 is 2311030131.

It is an interprime number because it is at equal distance from previous prime (13103011319) and next prime (13103011321).

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a self number, because there is not a number n which added to its sum of digits gives 13103011320.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13103011321) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7798572 + ... + 7800251.

It is an arithmetic number, because the mean of its divisors is an integer number (701947080).

Almost surely, 2^13103011320 is an apocalyptic number.

13103011320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13103011320 is an abundant number, since it is smaller than the sum of its proper divisors (31821601800).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13103011320 is a wasteful number, since it uses less digits than its factorization.

13103011320 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15598844 (or 15598840 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 13103011320 its reverse (2311030131), we get a palindrome (15414041451).

The spelling of 13103011320 in words is "thirteen billion, one hundred three million, eleven thousand, three hundred twenty".