Base | Representation |
---|---|
bin | 11101110010110000010101… |
… | …100100110011000011011000 |
3 | 122011221110111022100011020101 |
4 | 131302300111210303003120 |
5 | 114133303421400443300 |
6 | 1142402525144105144 |
7 | 36412456613110333 |
oct | 3562602544630330 |
9 | 564843438304211 |
10 | 131031224234200 |
11 | 38829037115454 |
12 | 1284288ba651b4 |
13 | 5816264743a44 |
14 | 244dd3348b61a |
15 | 102365215eb6a |
hex | 772c159330d8 |
131031224234200 has 96 divisors (see below), whose sum is σ = 323432840000160. Its totient is φ = 49197151180800.
The previous prime is 131031224234191. The next prime is 131031224234201. The reversal of 131031224234200 is 2432422130131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131031224234201) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 50392116 + ... + 52928515.
It is an arithmetic number, because the mean of its divisors is an integer number (3369092083335).
Almost surely, 2131031224234200 is an apocalyptic number.
131031224234200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131031224234200 is an abundant number, since it is smaller than the sum of its proper divisors (192401615765960).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131031224234200 is a wasteful number, since it uses less digits than its factorization.
131031224234200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 103321037 (or 103321028 counting only the distinct ones).
The product of its (nonzero) digits is 6912, while the sum is 28.
Adding to 131031224234200 its reverse (2432422130131), we get a palindrome (133463646364331).
The spelling of 131031224234200 in words is "one hundred thirty-one trillion, thirty-one billion, two hundred twenty-four million, two hundred thirty-four thousand, two hundred".
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