Base | Representation |
---|---|
bin | 11101110011110010011101… |
… | …110111110100110000101101 |
3 | 122012012020202211222010011122 |
4 | 131303302131313310300231 |
5 | 114140434331440300140 |
6 | 1142455311100430325 |
7 | 36420552325421162 |
oct | 3563623567646055 |
9 | 565166684863148 |
10 | 131102230400045 |
11 | 38856164261843 |
12 | 128545a78483a5 |
13 | 581cb6c476ba8 |
14 | 245354b978069 |
15 | 102540ac6dab5 |
hex | 773c9ddf4c2d |
131102230400045 has 16 divisors (see below), whose sum is σ = 173819427724800. Its totient is φ = 94420429872384.
The previous prime is 131102230400027. The next prime is 131102230400059. The reversal of 131102230400045 is 540004032201131.
It is a happy number.
It is not a de Polignac number, because 131102230400045 - 212 = 131102230395949 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 131102230399987 and 131102230400023.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (29) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 33529980245 + ... + 33529984154.
It is an arithmetic number, because the mean of its divisors is an integer number (10863714232800).
Almost surely, 2131102230400045 is an apocalyptic number.
It is an amenable number.
131102230400045 is a deficient number, since it is larger than the sum of its proper divisors (42717197324755).
131102230400045 is a wasteful number, since it uses less digits than its factorization.
131102230400045 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 67059964444.
The product of its (nonzero) digits is 2880, while the sum is 26.
Adding to 131102230400045 its reverse (540004032201131), we get a palindrome (671106262601176).
The spelling of 131102230400045 in words is "one hundred thirty-one trillion, one hundred two billion, two hundred thirty million, four hundred thousand, forty-five".
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