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13110230000 = 245471723479
BaseRepresentation
bin11000011010110111…
…00011101111110000
31020211200012200121002
430031123203233300
5203322204330000
610004525421132
7642612054620
oct141533435760
936750180532
1013110230000
11561842392a
12265a70a7a8
13130c18795a
148c5260880
1551ae778d5
hex30d6e3bf0

13110230000 has 400 divisors, whose sum is σ = 40163143680. Its totient is φ = 4038144000.

The previous prime is 13110229999. The next prime is 13110230011. The reversal of 13110230000 is 3201131.

It is a tau number, because it is divible by the number of its divisors (400).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 79 ways as a sum of consecutive naturals, for example, 27369761 + ... + 27370239.

Almost surely, 213110230000 is an apocalyptic number.

13110230000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13110230000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (20081571840).

13110230000 is an abundant number, since it is smaller than the sum of its proper divisors (27052913680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110230000 is a wasteful number, since it uses less digits than its factorization.

13110230000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 554 (or 533 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 11.

Adding to 13110230000 its reverse (3201131), we get a palindrome (13113431131).

The spelling of 13110230000 in words is "thirteen billion, one hundred ten million, two hundred thirty thousand".