131102340130000 has 100 divisors (see below), whose sum is σ = 325990575951700. Its totient is φ = 51023613312000.

The previous prime is 131102340129977. The next prime is 131102340130039. The reversal of 131102340130000 is 31043201131.

It can be written as a sum of positive squares in 10 ways, for example, as 52320455290944 + 78781884839056 = 7233288^2 + 8875916^2 .

It is a tau number, because it is divible by the number of its divisors (100).

It is a self number, because there is not a number n which added to its sum of digits gives 131102340130000.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 176795325 + ... + 177535324.

It is an arithmetic number, because the mean of its divisors is an integer number (3259905759517).

Almost surely, 2^{131102340130000} is an apocalyptic number.

131102340130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131102340130000 is an abundant number, since it is smaller than the sum of its proper divisors (194888235821700).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131102340130000 is an equidigital number, since it uses as much as digits as its factorization.

131102340130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 354330714 (or 354330693 counting only the distinct ones).

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 131102340130000 its reverse (31043201131), we get a palindrome (131133383331131).

The spelling of 131102340130000 in words is "one hundred thirty-one trillion, one hundred two billion, three hundred forty million, one hundred thirty thousand".