Base | Representation |
---|---|
bin | 1011111011000111110000… |
… | …0101101011101111000000 |
3 | 1201102100000212220102222121 |
4 | 2332301330011223233000 |
5 | 3204244414421131112 |
6 | 43514444313014024 |
7 | 2522122000515142 |
oct | 276617405535700 |
9 | 51370025812877 |
10 | 13110322052032 |
11 | 41a5069016307 |
12 | 1578a503b4314 |
13 | 7413b4b0454a |
14 | 334785cbcc92 |
15 | 17b069b97407 |
hex | bec7c16bbc0 |
13110322052032 has 28 divisors (see below), whose sum is σ = 26273377466856. Its totient is φ = 6490258438400.
The previous prime is 13110322052017. The next prime is 13110322052039. The reversal of 13110322052032 is 23025022301131.
It is a super-3 number, since 3×131103220520323 (a number of 40 digits) contains 333 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13110322051988 and 13110322052006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13110322052039) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1014096418 + ... + 1014109345.
Almost surely, 213110322052032 is an apocalyptic number.
It is an amenable number.
13110322052032 is an abundant number, since it is smaller than the sum of its proper divisors (13163055414824).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110322052032 is a wasteful number, since it uses less digits than its factorization.
13110322052032 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2028205876 (or 2028205866 counting only the distinct ones).
The product of its (nonzero) digits is 2160, while the sum is 25.
Adding to 13110322052032 its reverse (23025022301131), we get a palindrome (36135344353163).
The spelling of 13110322052032 in words is "thirteen trillion, one hundred ten billion, three hundred twenty-two million, fifty-two thousand, thirty-two".
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