Base | Representation |
---|---|
bin | 1011111011000111111000… |
… | …0100111110011101110000 |
3 | 1201102100010012200202122210 |
4 | 2332301332010332131300 |
5 | 3204300001441433130 |
6 | 43514451504132120 |
7 | 2522122554244653 |
oct | 276617604763560 |
9 | 51370105622583 |
10 | 13110355421040 |
11 | 41a50859379a9 |
12 | 1578a5b607040 |
13 | 7413bb9b8b17 |
14 | 33478a4c789a |
15 | 17b06ca895b0 |
hex | bec7e13e770 |
13110355421040 has 40 divisors (see below), whose sum is σ = 40642101805968. Its totient is φ = 3496094778880.
The previous prime is 13110355421029. The next prime is 13110355421077. The reversal of 13110355421040 is 4012455301131.
It is a tau number, because it is divible by the number of its divisors (40).
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a junction number, because it is equal to n+sod(n) for n = 13110355420989 and 13110355421007.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27313240221 + ... + 27313240700.
Almost surely, 213110355421040 is an apocalyptic number.
13110355421040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13110355421040 is an abundant number, since it is smaller than the sum of its proper divisors (27531746384928).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13110355421040 is a wasteful number, since it uses less digits than its factorization.
13110355421040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 54626480937 (or 54626480931 counting only the distinct ones).
The product of its (nonzero) digits is 7200, while the sum is 30.
The spelling of 13110355421040 in words is "thirteen trillion, one hundred ten billion, three hundred fifty-five million, four hundred twenty-one thousand, forty".
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