13111143401040 has 40 divisors (see below), whose sum is σ = 40644544543968. Its totient is φ = 3496304906880.

The previous prime is 13111143401033. The next prime is 13111143401051. The reversal of 13111143401040 is 4010434111131.

It is a tau number, because it is divible by the number of its divisors (40).

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a self number, because there is not a number n which added to its sum of digits gives 13111143401040.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 27314881846 + ... + 27314882325.

Almost surely, 2^{13111143401040} is an apocalyptic number.

13111143401040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13111143401040 is an abundant number, since it is smaller than the sum of its proper divisors (27533401142928).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111143401040 is a wasteful number, since it uses less digits than its factorization.

13111143401040 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 54629764187 (or 54629764181 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 24.

Adding to 13111143401040 its reverse (4010434111131), we get a palindrome (17121577512171).

The spelling of 13111143401040 in words is "thirteen trillion, one hundred eleven billion, one hundred forty-three million, four hundred one thousand, forty".