Base | Representation |
---|---|
bin | 1011111011001011000100… |
… | …0101111001110101011000 |
3 | 1201102102022212012000221012 |
4 | 2332302301011321311120 |
5 | 3204303230043132412 |
6 | 43515112440433052 |
7 | 2522153016152261 |
oct | 276626105716530 |
9 | 51372285160835 |
10 | 13111211302232 |
11 | 41a5484a7612a |
12 | 157905a178788 |
13 | 7414c7105cb4 |
14 | 33482c03b968 |
15 | 17b0bcc9dc22 |
hex | becb1179d58 |
13111211302232 has 64 divisors (see below), whose sum is σ = 25514215833600. Its totient is φ = 6309727632000.
The previous prime is 13111211302171. The next prime is 13111211302253. The reversal of 13111211302232 is 23220311211131.
It is a happy number.
It is a super-2 number, since 2×131112113022322 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 13111211302198 and 13111211302207.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 283284869 + ... + 283331147.
It is an arithmetic number, because the mean of its divisors is an integer number (398659622400).
Almost surely, 213111211302232 is an apocalyptic number.
It is an amenable number.
13111211302232 is a deficient number, since it is larger than the sum of its proper divisors (12403004531368).
13111211302232 is a wasteful number, since it uses less digits than its factorization.
13111211302232 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 52488 (or 52484 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 13111211302232 its reverse (23220311211131), we get a palindrome (36331522513363).
The spelling of 13111211302232 in words is "thirteen trillion, one hundred eleven billion, two hundred eleven million, three hundred two thousand, two hundred thirty-two".
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