13111223131032 has 64 divisors (see below), whose sum is σ = 35318355502080. Its totient is φ = 4032061517952.

The previous prime is 13111223130997. The next prime is 13111223131033. The reversal of 13111223131032 is 23013132211131.

It is a super-2 number, since 2×13111223131032² (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (24).

It is a junction number, because it is equal to n+sod(n) for n = 13111223130993 and 13111223131011.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111223131033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10671688 + ... + 11836695.

It is an arithmetic number, because the mean of its divisors is an integer number (551849304720).

Almost surely, 2^{13111223131032} is an apocalyptic number.

13111223131032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13111223131032 is an abundant number, since it is smaller than the sum of its proper divisors (22207132371048).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111223131032 is a wasteful number, since it uses less digits than its factorization.

13111223131032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 22510272 (or 22510268 counting only the distinct ones).

The product of its (nonzero) digits is 648, while the sum is 24.

Adding to 13111223131032 its reverse (23013132211131), we get a palindrome (36124355342163).

The spelling of 13111223131032 in words is "thirteen trillion, one hundred eleven billion, two hundred twenty-three million, one hundred thirty-one thousand, thirty-two".