13111433133040 has 160 divisors (see below), whose sum is σ = 33529411123200. Its totient is φ = 4728626242560.

The previous prime is 13111433133037. The next prime is 13111433133041. The reversal of 13111433133040 is 4033133411131.

It is a happy number.

It is a super-2 number, since 2×13111433133040² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111433133041) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 68612346 + ... + 68803174.

It is an arithmetic number, because the mean of its divisors is an integer number (209558819520).

Almost surely, 2^{13111433133040} is an apocalyptic number.

13111433133040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13111433133040, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (16764705561600).

13111433133040 is an abundant number, since it is smaller than the sum of its proper divisors (20417977990160).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111433133040 is a wasteful number, since it uses less digits than its factorization.

13111433133040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 191495 (or 191489 counting only the distinct ones).

The product of its (nonzero) digits is 3888, while the sum is 28.

Adding to 13111433133040 its reverse (4033133411131), we get a palindrome (17144566544171).

The spelling of 13111433133040 in words is "thirteen trillion, one hundred eleven billion, four hundred thirty-three million, one hundred thirty-three thousand, forty".