Base | Representation |
---|---|
bin | 111101000011110001… |
… | …1110000000111001001 |
3 | 110112110012122120022110 |
4 | 1322013203300013021 |
5 | 4122020032041040 |
6 | 140123123412533 |
7 | 12321233534424 |
oct | 1720743600711 |
9 | 415405576273 |
10 | 131123315145 |
11 | 50677769459 |
12 | 214b4b24149 |
13 | c498829854 |
14 | 64bc7569bb |
15 | 36267a2980 |
hex | 1e878f01c9 |
131123315145 has 64 divisors (see below), whose sum is σ = 224816290560. Its totient is φ = 65028096000.
The previous prime is 131123315137. The next prime is 131123315149. The reversal of 131123315145 is 541513321131.
It is not a de Polignac number, because 131123315145 - 23 = 131123315137 is a prime.
It is a super-3 number, since 3×1311233151453 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a Curzon number.
It is not an unprimeable number, because it can be changed into a prime (131123315149) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 12640521 + ... + 12650889.
It is an arithmetic number, because the mean of its divisors is an integer number (3512754540).
Almost surely, 2131123315145 is an apocalyptic number.
131123315145 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
131123315145 is a deficient number, since it is larger than the sum of its proper divisors (93692975415).
131123315145 is a wasteful number, since it uses less digits than its factorization.
131123315145 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 10986.
The product of its digits is 5400, while the sum is 30.
Adding to 131123315145 its reverse (541513321131), we get a palindrome (672636636276).
The spelling of 131123315145 in words is "one hundred thirty-one billion, one hundred twenty-three million, three hundred fifteen thousand, one hundred forty-five".
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