1311240040100 has 72 divisors (see below), whose sum is σ = 2861009550336. Its totient is φ = 521618400000.

The previous prime is 1311240040069. The next prime is 1311240040133. The reversal of 1311240040100 is 10400421131.

It is a happy number.

It is a super-2 number, since 2×1311240040100² (a number of 25 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 117478520 + ... + 117489680.

Almost surely, 2^{1311240040100} is an apocalyptic number.

1311240040100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 1311240040100, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1430504775168).

1311240040100 is an abundant number, since it is smaller than the sum of its proper divisors (1549769510236).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311240040100 is a wasteful number, since it uses less digits than its factorization.

1311240040100 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 17517 (or 17510 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 17.

Adding to 1311240040100 its reverse (10400421131), we get a palindrome (1321640461231).

The spelling of 1311240040100 in words is "one trillion, three hundred eleven billion, two hundred forty million, forty thousand, one hundred".