Base | Representation |
---|---|
bin | 1011111011010001110011… |
… | …1010101110011000111100 |
3 | 1201102120222221011012120122 |
4 | 2332310130322232120330 |
5 | 3204320431144423400 |
6 | 43520012142034112 |
7 | 2522245603400513 |
oct | 276643472563074 |
9 | 51376887135518 |
10 | 13113020311100 |
11 | 41a6223123286 |
12 | 1579483b78938 |
13 | 741724b2b748 |
14 | 3349603bb67a |
15 | 17b1769d6685 |
hex | bed1ceae63c |
13113020311100 has 36 divisors (see below), whose sum is σ = 28580607666744. Its totient is φ = 5222101471680.
The previous prime is 13113020311093. The next prime is 13113020311103. The reversal of 13113020311100 is 111302031131.
It is a super-2 number, since 2×131130203111002 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13113020311103) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 288810347 + ... + 288855746.
Almost surely, 213113020311100 is an apocalyptic number.
13113020311100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13113020311100 is an abundant number, since it is smaller than the sum of its proper divisors (15467587355644).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13113020311100 is a wasteful number, since it uses less digits than its factorization.
13113020311100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 577666334 (or 577666327 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 13113020311100 its reverse (111302031131), we get a palindrome (13224322342231).
The spelling of 13113020311100 in words is "thirteen trillion, one hundred thirteen billion, twenty million, three hundred eleven thousand, one hundred".
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