Base | Representation |
---|---|
bin | 111101000100000000… |
… | …1000101000110100100 |
3 | 110112110202010011110221 |
4 | 1322020001011012210 |
5 | 4122024014101200 |
6 | 140124000254124 |
7 | 12321356065033 |
oct | 1721001050644 |
9 | 415422104427 |
10 | 131131003300 |
11 | 5068103a700 |
12 | 214b7611344 |
13 | c49a2bc05b |
14 | 64bd79871a |
15 | 36272c091a |
hex | 1e880451a4 |
131131003300 has 108 divisors (see below), whose sum is σ = 313551098980. Its totient is φ = 47565619200.
The previous prime is 131131003279. The next prime is 131131003321. The reversal of 131131003300 is 3300131131.
It is an interprime number because it is at equal distance from previous prime (131131003279) and next prime (131131003321).
It can be written as a sum of positive squares in 6 ways, for example, as 15134904576 + 115996098724 = 123024^2 + 340582^2 .
It is a super-2 number, since 2×1311310033002 (a number of 23 digits) contains 22 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 4935652 + ... + 4962148.
Almost surely, 2131131003300 is an apocalyptic number.
131131003300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131131003300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (156775549490).
131131003300 is an abundant number, since it is smaller than the sum of its proper divisors (182420095680).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131131003300 is a wasteful number, since it uses less digits than its factorization.
131131003300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 26942 (or 26924 counting only the distinct ones).
The product of its (nonzero) digits is 81, while the sum is 16.
Adding to 131131003300 its reverse (3300131131), we get a palindrome (134431134431).
The spelling of 131131003300 in words is "one hundred thirty-one billion, one hundred thirty-one million, three thousand, three hundred".
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