Search a number
-
+
131131003300 = 225211240926497
BaseRepresentation
bin111101000100000000…
…1000101000110100100
3110112110202010011110221
41322020001011012210
54122024014101200
6140124000254124
712321356065033
oct1721001050644
9415422104427
10131131003300
115068103a700
12214b7611344
13c49a2bc05b
1464bd79871a
1536272c091a
hex1e880451a4

131131003300 has 108 divisors (see below), whose sum is σ = 313551098980. Its totient is φ = 47565619200.

The previous prime is 131131003279. The next prime is 131131003321. The reversal of 131131003300 is 3300131131.

It is an interprime number because it is at equal distance from previous prime (131131003279) and next prime (131131003321).

It can be written as a sum of positive squares in 6 ways, for example, as 15134904576 + 115996098724 = 123024^2 + 340582^2 .

It is a super-2 number, since 2×1311310033002 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 4935652 + ... + 4962148.

Almost surely, 2131131003300 is an apocalyptic number.

131131003300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131131003300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (156775549490).

131131003300 is an abundant number, since it is smaller than the sum of its proper divisors (182420095680).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131131003300 is a wasteful number, since it uses less digits than its factorization.

131131003300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 26942 (or 26924 counting only the distinct ones).

The product of its (nonzero) digits is 81, while the sum is 16.

Adding to 131131003300 its reverse (3300131131), we get a palindrome (134431134431).

The spelling of 131131003300 in words is "one hundred thirty-one billion, one hundred thirty-one million, three thousand, three hundred".

Divisors: 1 2 4 5 10 11 20 22 25 44 50 55 100 110 121 220 242 275 409 484 550 605 818 1100 1210 1636 2045 2420 3025 4090 4499 6050 8180 8998 10225 12100 17996 20450 22495 26497 40900 44990 49489 52994 89980 98978 105988 112475 132485 197956 224950 247445 264970 291467 449900 494890 529940 582934 662425 989780 1165868 1237225 1324850 1457335 2474450 2649700 2914670 3206137 4948900 5829340 6412274 7286675 10837273 12824548 14573350 16030685 21674546 29146700 32061370 43349092 54186365 64122740 80153425 108372730 119210003 160306850 216745460 238420006 270931825 320613700 476840012 541863650 596050015 1083727300 1192100030 1311310033 2384200060 2622620066 2980250075 5245240132 5960500150 6556550165 11921000300 13113100330 26226200660 32782750825 65565501650 131131003300