Base | Representation |
---|---|
bin | 111101000100000100… |
… | …0110110011001011100 |
3 | 110112110212221122121102 |
4 | 1322020020312121130 |
5 | 4122030024241340 |
6 | 140124112052232 |
7 | 12321412310420 |
oct | 1721010663134 |
9 | 415425848542 |
10 | 131133040220 |
11 | 50682201006 |
12 | 214b8234078 |
13 | c49a853230 |
14 | 64bdb68b80 |
15 | 3627574215 |
hex | 1e8823665c |
131133040220 has 96 divisors (see below), whose sum is σ = 340703870976. Its totient is φ = 41284051200.
The previous prime is 131133040219. The next prime is 131133040307. The reversal of 131133040220 is 22040331131.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 131133040192 and 131133040201.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 159005 + ... + 536235.
It is an arithmetic number, because the mean of its divisors is an integer number (3548998656).
Almost surely, 2131133040220 is an apocalyptic number.
131133040220 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131133040220, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (170351935488).
131133040220 is an abundant number, since it is smaller than the sum of its proper divisors (209570830756).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131133040220 is a wasteful number, since it uses less digits than its factorization.
131133040220 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 377451 (or 377449 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 20.
Adding to 131133040220 its reverse (22040331131), we get a palindrome (153173371351).
The spelling of 131133040220 in words is "one hundred thirty-one billion, one hundred thirty-three million, forty thousand, two hundred twenty".
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